(1-x)^2+(1-x/2)^2=1

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Solution for (1-x)^2+(1-x/2)^2=1 equation: 



(1-x)^2+(1-x/2)^2=1

We move all terms to the left:

(1-x)^2+(1-x/2)^2-(1)=0

We add all the numbers together, and all the variables

(-1x+1)^2+(-x/2+1)^2-1=0

We multiply all the terms by the denominator


((-1x+1)^2)*2-x+1)^2+(-1*2+1)^2=0

We add all the numbers together, and all the variables

((-1x+1)^2)*2-x+1)^2+(-1)^2=0

We add all the numbers together, and all the variables

-1x+((-1x+1)^2)*2=0

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